please answer this question as fast as possible.......with full explanation......
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hey mate , here is ur answer
GIVEN Intial velocity = 50ms
time = 10sec
final velocity = 0( it will come to rest )
now ,
1. acceleration = v-u/t ( final velocity - intial velocity / time taken)
0-50/10
-50/10
-5ms^2
2. distance covered
s = ut+1/2at^2 ( distance = intial velo. × time + 1/2 × acceleration × time ^2 )
(50×10) + (1/2× -5 × 10 ×10)
500 + ( -250 )
500 - 250 = 250ms
hope it helps u..✌✌
GIVEN Intial velocity = 50ms
time = 10sec
final velocity = 0( it will come to rest )
now ,
1. acceleration = v-u/t ( final velocity - intial velocity / time taken)
0-50/10
-50/10
-5ms^2
2. distance covered
s = ut+1/2at^2 ( distance = intial velo. × time + 1/2 × acceleration × time ^2 )
(50×10) + (1/2× -5 × 10 ×10)
500 + ( -250 )
500 - 250 = 250ms
hope it helps u..✌✌
Khushisaini:
thanks
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