Math, asked by jagadhes1979, 8 months ago

please answer this question as quick as possible​

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Answered by MysticPetals
5

Answer:

Two liquids are at 40°C and 30° C

=> equal masses at a temp of 36°C

We need to subtract the specific liquid's temperature and the one which is been mixed later. See,

Let the two liquids be named as A(40°C)and B(30°C)

Specific heat of A = (40 - 36)°C = 4°C

Specific heat of B = ( 36 - 30)°C = 6° C

Now let's make a ratio of specific heat of A and B = 4 : 6

after simplifying The ratio becomes as 2:3

Option (2) is the right answer

Hope this helps you friend

Answered by SASITN
2

Answer:

  • option 1 is correct

Step-by-step explanation:

please do refer to the attachment

hope this helps you

to better understand refer 11th state board book - pg 106-107

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