please answer this question as quick as possible
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☆Given:
♢ Air bubbles starts from bottom to top !
♢ Radius is doubled ( 2 r) on reaching the surface from the bottom.
♡ Bottom of lake = r metre
♡ At the surface = 2r metre [ since it's doubled]
♢ Temperature remains constant
¤ which means its an isothermal process !!
☆ Condition for Isothermal process:
PV = Constant
P1 V1 = P2V2
Final pressure (P2)=1 atm.pressure(given)=10 m
Initial pressure (P1)=atm.pressure+ pressure of height ( surface)
P1 = (10+ h) metre.
☆ Volume of sphere=4/3 π r^3
Initial volume ( V1)= 4/3 π r^3
Final volume (V2) =4/3π (2r)^3
=》 V2 = 8 V1
Then
P1V1 = P2V2
substitute the values
=> ( 10+ h)V1 = 10 * 8 v1
Hence the height becomes 70 metre
=> The answer is 70 m. hope this helps u!
Kindly refer the attachment if needed :-)
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The answer is 70cm....
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