Math, asked by PrinceVegeta, 1 year ago

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PrinceVegeta: 3cos43/sin47- cos37*cosec53/tan5*tan25*tan45*tan65*tan85 - cos^2 0

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Answered by rohitkumargupta
7
HELLO DEAR,


3( \frac{ \cos( 43) }{ \sin(47) } ) -  \frac{ \cos(37) \cosec(53)  }{ \tan(5)  \times  \tan(25)  \times  \tan(45) \tan(65)  \tan(85)  }  -  { \cos }^{2} 0 \\  =  > 3( \frac{ \cos(90 - 47) }{ \sin(47) } ) -  \frac{ \cos(90 - 53) cosec(53)}{ \tan(90 - 85)  \times  \tan(85) \times  \tan(90 -65 )   \times  \tan(65)  \times  \tan(45) }   -  {1}^{2} \\  =  > 3( \frac{ \sin(47) }{ \sin(47) } ) -  \frac{ \sin(53)  \times  \frac{1}{ \sin(53) }  }{ \cot(85)  \times  \frac{1}{ \cot(85) }  \times \cot(65)   \times  \frac{1}{  \cot(65)  } \times 1 }  - 1 \\  =  > 3 - 1 - 1 = 1
I HOPE ITS HELP YOU DEAR,
THANKS
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