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let ABCD be the quadrilateral,
by finding length of AB,BC,CD,AC.
and diagonalsAD,andBC.
all lengths found will be equal.
and two diagonals.then find the area of quadrilateral by 1\2×d1×d2
by finding length of AB,BC,CD,AC.
and diagonalsAD,andBC.
all lengths found will be equal.
and two diagonals.then find the area of quadrilateral by 1\2×d1×d2
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=1/2{(25 +24-5+28)-(-28+5-24-25)}
=1/2{(77-5)-(-77+5)}
=1/2{(72)-(72)}
=1/2{(72+72)}
=1/2(144)
=72 sq. units.
=1/2{(77-5)-(-77+5)}
=1/2{(72)-(72)}
=1/2{(72+72)}
=1/2(144)
=72 sq. units.
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