Question

Please answer this question as soon as possible.
I want full explanation.

Answer 1

a 60% 120% thats better try

Answer 2

From figure:

In ΔDAM and ΔDBM,

⇒ ∠AMD = ∠BMD

⇒ AM = BM

⇒ DM = DM

⇒ ΔDAM ≅ ΔDBM {SAS rule}

⇒ AD = BD = AB

Since, ABD is an equilateral triangle,

⇒ ∠A = 60°.

Now,

⇒ AD || BC and AB is traversal,

⇒ ∠A + ∠B = 180° {Interior angles}

⇒ 60° + ∠B = 180°

⇒ ∠B = 120°

We know that opposite angles of a parallelogram are equal.

⇒ ∠A = ∠C = 60°.

⇒ ∠B = ∠D = 120°.

Therefore:

⇒ ∠A = 60°

⇒ ∠B = 120°

Hope it helps!