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Given:-
AC=DF
BC=EF
To Prove:-
(i) ΔABC≅ΔDEF
(ii) AB= DE
Proof:-
In ΔABC and ΔDEF
∠B=∠E (90°)
AC=DF (Given)
BC=EF (Given)
By RHS congruency:- ΔABC≅ΔDEF
By CPCT:- AB=DE
Hence proved
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