Question

Please answer this question asap

Answer 1

$x=\sqrt{12+\sqrt{12+\sqrt{12+\sqrt{12+...inf }$

$=> x = \sqrt{12+x} } \\\\=> x^2 = 12+x\\=> x^2-x-12=0\\=>x^2-4x+3x-12=0\\=>x(x-4)+3(x-4)=0\\=>(x-4)(x+3)=0\\=>x=4,-3$

But we know that x is a square root so it must always be positive.

Hence, the value of x should be 4 and not -3.

Ans :- Value of x is 4.

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