Question

Please answer this question at the earliest

Answer 1

Step-by-step explanation:

$\large{\gray{\underline{\underline{\mathsf{Given:-}}}}}$

$BM \perp AD$

$CN \perp AN$

D is mid point of BC.

$\large{\gray{\underline{\underline{\mathsf{To\:Prove:-}}}}}$

1. ∆BMD ≅ ∆CND
2. BM = CN

$\large{\gray{\underline{\underline{\mathsf{Solution:-}}}}}$

In ∆BMD and in ∆CND,

• ∠BMD = ∠CND (each 90°)
• BD = DC (D is mid point)
• ∠MDB = ∠CDN (Vertically opposite angles)

So, by AAS rule, ∆BMD ≅ ∆CND

and, by CPCT rule, BM = CN

$\large{\gray{\underline{\underline{\mathsf{Hence\:Proved}}}}}$