PLEASE ANSWER THIS QUESTION
B is twice as efficient as A, who works half as fast as C. If A, B and C can complete a piece of work in 20 days. In how days can B and C together complete it?
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4
Given that :- A is half as efficient as C And B is twice as efficient as A.
Let the number of days taken by C to complete the work be a
Number of days taken by B to complete the work = a
Number of days taken by A to complete the work = 2a
A's one day work = 1/2a
B's one day work = 1/a
C's one day work = 1/a
( A + B + C)'s one day work = ( 1/2a + 1/a+1/a)
= ( 1 + 2+ 2)/ 2a
= 5/2a
Time taken by A, B and C to finish the work = 2a/5
=> 20 = 2a/5
=> 2a = 100
=> a = 50
B's one day work = 1/50
C's one day work = 1/50
( B + C)'s one day work = ( 1/50 + 1/50)
= ( 1 +1) /50
= 2/50
= 1/25
Time taken by B and C to finish the work = 25 days..
Let the number of days taken by C to complete the work be a
Number of days taken by B to complete the work = a
Number of days taken by A to complete the work = 2a
A's one day work = 1/2a
B's one day work = 1/a
C's one day work = 1/a
( A + B + C)'s one day work = ( 1/2a + 1/a+1/a)
= ( 1 + 2+ 2)/ 2a
= 5/2a
Time taken by A, B and C to finish the work = 2a/5
=> 20 = 2a/5
=> 2a = 100
=> a = 50
B's one day work = 1/50
C's one day work = 1/50
( B + C)'s one day work = ( 1/50 + 1/50)
= ( 1 +1) /50
= 2/50
= 1/25
Time taken by B and C to finish the work = 25 days..
MERCURY1234:
no
Ok
B is twice as efficient as A, it means A is half as efficient as B
ok
and A is half as efficient as C too, so both are same
ok
now i understood
thanks bro
please answer my question
fast
Answered by
1
Given that :- A is half as efficient as C And B is twice as efficient as A.
Let the number of days taken by C to complete the work be a
Number of days taken by B to complete the work = a
Number of days taken by A to complete the work = 2a
A's one day work = 1/2a
B's one day work = 1/a
C's one day work = 1/a
( A + B + C)'s one day work = ( 1/2a + 1/a+1/a)
= ( 1 + 2+ 2)/ 2a
= 5/2a
Time taken by A, B and C to finish the work = 2a/5
=> 20 = 2a/5
=> 2a = 100
=> a = 50
B's one day work = 1/50
C's one day work = 1/50
( B + C)'s one day work = ( 1/50 + 1/50)
= ( 1 +1) /50
= 2/50
= 1/25
Time taken by B and C to finish the work = 25 days..
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