Question

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Answer 1

Note: I'm using '*' to denote degrees. I'm just lazy.

The angle at which the ray would initially be reflected at, will be 55*.

So, the angle CAB is 90* - 55* = 35*.

And the angle ACB in the triangle ACB = 180* - (120* + 35*) = 25*.

And the angle complementary to it - the one the final incident makes with the final normal, is, obviously, 90* - 25* = 65*.

Finally, using incident angle = you know what, x = 65*.

Answer 2

Answer:

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