Question

Please answer this question before 31/12/2020.

Answer 1

Answer:

here a=9.8

distance=1000m

from 3rd law of motion

v²= u²+2as

0= u²+2*-9.8*1000

-u²= -19600

u² = 19600

u= 140 m/s

and,

from 1st law of motion

v= u +at

0=140 - 9.8t

-140 = -9.8t

140=9.8t

t = 1400/98

t =14.3 sec

t = 14 sec. (approximately).

Explanation:

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