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Bunti360:
25 m/s²
apply , 2nd equation of motion
s = ut + 0.5 gt², Here u = 0, As freely falling objects won't have initial velocity
Now, 50 = 0.5*g*(2)²
100/4 = g = 25 m/s²
Hope you understand !.
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hii friend....
ans :- b
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ans :- b
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Here is the solution :
Let the gravity on unknown planet be g,
The second equation can help us to know the value of g ,
Given that,
s (height ) = displacement = 50 m,
Here height = displacement as it's linear,
time taken by the body to fall = 2 secs,
We know that, For a freely falling body, the initial velocity is 0, As no-one applies a force neither does someone throw it with certain velocity, It just freely falls,
2nd Equation of motion : s = ut + (1/2)*g*t²,
s = -50 m, (It's downwards or it falls down)
u = 0,
t = 2 secs,
g = -g as it acts downwards,
=> (-50)m = 0*t m/s * sec - (0.5)*g*t² sec²
=> -50 m = -0.5*4 *g sec²
=> 25 m/sec² = g
Therefore, The gravity on unknown planet is 25 m/sec²
=> Option (b) is correct,
Hope you understand, Have a great day,
Thanking you, Bunti 360 !.
Let the gravity on unknown planet be g,
The second equation can help us to know the value of g ,
Given that,
s (height ) = displacement = 50 m,
Here height = displacement as it's linear,
time taken by the body to fall = 2 secs,
We know that, For a freely falling body, the initial velocity is 0, As no-one applies a force neither does someone throw it with certain velocity, It just freely falls,
2nd Equation of motion : s = ut + (1/2)*g*t²,
s = -50 m, (It's downwards or it falls down)
u = 0,
t = 2 secs,
g = -g as it acts downwards,
=> (-50)m = 0*t m/s * sec - (0.5)*g*t² sec²
=> -50 m = -0.5*4 *g sec²
=> 25 m/sec² = g
Therefore, The gravity on unknown planet is 25 m/sec²
=> Option (b) is correct,
Hope you understand, Have a great day,
Thanking you, Bunti 360 !.
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