please answer this question..best answer will be marked as a brainliest answer...and I will also begin to follow them....ready to get 20 points...
Answers
Answer:
Hey!!
Step-by-step explanation:
Let height of the cone 1 be 'h' cm and the height of the cone 2 be (21 cm - h) .
Volume of cone 1/Volume of cone 1 = 2/1
⇒ {1/3πr²h} / {1/3πr²(21 cm - h)} = 2/1
⇒ 42 cm - 2h = h
⇒ 3h = 42 cm
⇒ h = 42/3
⇒ h = 14 cm
Height of the 1 st cone is 14 cm and the height of the 2nd cone is 21 - 14 = 7 cm.
Now,
Volume of cone 1 = 1/3*22/7*3*3*14
= 132 cm³ or Capacity = 0.132 liters
Volume of cone 2 = 1/3*22/7*3*3*7
= 66 cm³ or capacity = 0.066 liters
Volume of cylinder = πr²h
= 22/7*3*3*21
= 594 cm³
Remaining volume = 594 - 198
= 396 cm³
Thank You..
Answer:
Hey!!
Step-by-step explanation:
Let height of the cone 1 be 'h' cm and the height of the cone 2 be (21 cm - h) .
Volume of cone 1/Volume of cone 1 = 2/1
⇒ {1/3πr²h} / {1/3πr²(21 cm - h)} = 2/1
⇒ 42 cm - 2h = h
⇒ 3h = 42 cm
⇒ h = 42/3
⇒ h = 14 cm
Height of the 1 st cone is 14 cm and the height of the 2nd cone is 21 - 14 = 7 cm.
Now,
Volume of cone 1 = 1/3*22/7*3*3*14
= 132 cm³ or Capacity = 0.132 liters
Volume of cone 2 = 1/3*22/7*3*3*7
= 66 cm³ or capacity = 0.066 liters
Volume of cylinder = πr²h
= 22/7*3*3*21
= 594 cm³
Remaining volume = 594 - 198
= 396 cm³
Thank You..