Question

please answer this question by doing methods it's urgent​

Answer 1

1) max.speed is 10 m/s b/w time interval 40-420 s

2)acceleration is slope of V-t graph

Acceleration in OA

= 10/40 = 1/4

IN AB ITS zero as velocity is constant

In BC = -10/ 80 = -1/8

3)total distance

Its Area

Area = 1/2 ( 380+500) × 10

= 5( 880)

= 4440

So distance = 4440 m