Question

Please Answer this Question By Sending Photo pls ​

Answer 1

Answer:

I have attached the solution

hope it helps you :)

Answer 2

Step-by-step explanation:

$\sf \frac { {x}^{2} + sinx }{ 1 + x }$

$\sf Here\:we\:have\:to\:use\:division\:rule$

$\sf Differentiating \:w.r.t.\: x$

$\sf \frac {dy}{dx} = \frac {( 1 + x ) \frac {d ({x}^{2} + sinx }{dx } -( {x}^{2} + sinx ) \frac {d ( 1 + x )}{dx} }{{(1+x)}^{2}}$

$\sf \frac {dy}{dx} = \frac { ( 1+ x ) (2x + cosx ) - {x}^{2} - sinx }{{(1+x)}^{2}}$

$\sf \frac {dy}{dx} = \frac { 2x + {x}^{2} + cosx - sinx }{ {(1 + x)}^{2}}$

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