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∠SRP = 20 degree
∠ SRP = ∠a (alternate angles)
= 20 degree
∠PRQ = 50 degree
∠PRQ = ∠b ( alternate angles)
= 50 degree
Therefore, ∠a is 20 degree
∠b is 50 degree
Hope it helps ....
∠ SRP = ∠a (alternate angles)
= 20 degree
∠PRQ = 50 degree
∠PRQ = ∠b ( alternate angles)
= 50 degree
Therefore, ∠a is 20 degree
∠b is 50 degree
Hope it helps ....
Answered by
0
if PQ//SR and SP//RQ then PR is the transversal
THEREFORE,
angle b and angle prq are corresponding angles
hence b=50°
AND
angle a and angle SRP are corresponding angles and corresponding angles are equal
hence a=20°
THEREFORE,
angle b and angle prq are corresponding angles
hence b=50°
AND
angle a and angle SRP are corresponding angles and corresponding angles are equal
hence a=20°
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