Question

Please Answer this question


. challenge for you.​

Answer 1

a²x³-a⁴y²=1

Step-by-step explanation:

X⁶+a²x³y/x⁶-a⁴y²=

x⁶+a²x⁹y-a⁴y²x⁶/x⁶=

x⁶(a²x³y-a⁴y²)=x⁶ a²x³y-a⁴y²=1

Answer 2

→ Hey Mate,

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→ Given Question:-

→  $\frac{x^6 + a^2x^3 y}{x^6 - a^4y^2}$

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→ Formula Used:-

→  α² - b² = ( α + b) ( α-b)

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→ Solution:-

→ $x^6 - a^4y^2 = ( x^3 )^2 - (a^2y)^2$

→                 $= (x^3 + a^2y) ( x^3 - a^2y)$

→ $x^6 +a^2x^3y = x^3 (x^3 + a^2y)$

→ $x^6-a^4y^2 = ( x^3 + a^2y)(x^3 -a^2y)$

→ $\frac{x^6 +a^2x^3y}{x^6 - a^4y^2} = \frac{x^3 (x^3+a^2y)}{( x^3 +a^2y)(x^3 -a^2y)}$

→ Just cancel ⇒ $\frac{(x^3 + a^2y)}{(x^3 + a^2y)}$

→  $\frac{x^3}{x^3-a^2y}$

→ $\frac{x^3}{x^3-a^2y}$ is the Final Answer.

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