Question

please answer this question.. chapter: understanding Quadrilaterals​

Answer 1

Answer:

• Given - Triangle ABC

- angle a = (x + 10 )°

- angle b = (3x + 5) °

- angle C = (2x + 15)°

• To find - Value of X

• Solution

We know that sum of all angles of a triangle is 180 °

angle a + angle b + angle C = 180°

x + 10 + 3x + 5 + 2x + 15 = 180°

X + 3x + 2x + 10 + 5 + 15 = 180°

6x + 30 = 180°

6x = 180 - 30

6x = 150

x= 150/6

X = 50/2

= 25 °

X= 25°

More to find

Angle a =

X + 10

25 + 10

35°

Angle B

3x + 5

3(25) + 5

75+ 5

80°

Angle C

2x + 15

2( 25 ) + 15

50 + 15

65°

Answer 2

Answer:

In angleABC,

angleA+angleB+angleC=180°

→x+10°+3x+5°+2x+15°=180°

→6x+30°=180°

→6x=180°-30°

→6x=150°

→x=150°/6

→x=25°

angleA=x+10°=25°+10°=35°

angleB=3x+5°=3×25°+5°=80°

angleC=2x+15°=2×25°+15°=65°

Step-by-step explanation:

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