Math, asked by Aditishinde, 1 year ago

please answer this question correct answer will be marked brainliest

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Grimmjow: i didn't see what you have commented, because it was deleted. .i want to know what is the answer for this question.

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Answered by dhruvmadhur1123
0

Then you must be mark me as brainliest

AD=28 cm

AB+BC+CD  = 28 [AD = AB+BC+CD ]

AB+AB+AB+AB = 28  [because BC= 2AB = AB+AB   & AB = AC]

4AB = 28

AB = 7 cm

Now area of semicircle with diameter = 28 cm

radius, r = 14 cm

area = π r^2

= 22/7 * 14 * 14

=616 cm^2

again, area of semicircle with diameter BC = 2AB = 14 cm

radius, R = 7 cm

area = π R^2

= 22/7 * 7 * 7

=154 cm^2

again, area of semicircle with diameter AB = 7 cm

radius, t (let us assume)  = 7/2

area = π t^2

=22/7 * 7/2 * 7/2

= 38.5 cm^2

now area of semicircle with diameter CD = 7 cm = 38.5 cm^2

Area of shaded region = [616 + 154 - {38.5 + 38.5}] cm^2

=[770 - 77] cm^2

= 693 cm^2

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