Please answer this question correct, no wrong answers please!
Answers
Answer:
Combine multiplied terms into a single fraction
1
3
(
3
+
5
)
+
1
3
(
4
−
5
)
=
9
\frac{1}{3}(3x+5)+\frac{1}{3}(4x-5)=9
31(3x+5)+31(4x−5)=9
1
(
3
+
5
)
3
+
1
3
(
4
−
5
)
=
9
\frac{1(3x+5)}{3}+\frac{1}{3}(4x-5)=9
31(3x+5)+31(4x−5)=9
2
Multiply by 1
1
(
3
+
5
)
3
+
1
3
(
4
−
5
)
=
9
\frac{1(3x+5)}{3}+\frac{1}{3}(4x-5)=9
31(3x+5)+31(4x−5)=9
3
+
5
3
+
1
3
(
4
−
5
)
=
9Combine multiplied terms into a single fraction
3
+
5
3
+
1
3
(
4
−
5
)
=
9
\frac{3x+5}{3}+\frac{1}{3}(4x-5)=9
33x+5+31(4x−5)=9
3
+
5
3
+
1
(
4
−
5
)
3
=
93
+
5
3
+
1
(
4
−
5
)
3
=
9
\frac{3x+5}{3}+\frac{1(4x-5)}{3}=9
33x+5+31(4x−5)=9
3
+
5
3
+
4
−
5
3
=
9
\frac{3x+5}{3}+\frac{4x-5}{3}=9
33x+5+34x−5=9
53
+
5
3
+
4
−
5
3
=
9
\frac{3x+5}{3}+\frac{4x-5}{3}=9
33x+5+34x−5=9
3
+
5
+
4
−
5
3
=
9
\frac{3x+5+4x-5}{3}=9
33x+5+4x−5=9
6
Subtract the numbers
3
+
5
+
4
−
5
3
=
9
\frac{3x+{\color{#c92786}{5}}+4x{\color{#c92786}{-5}}}{3}=9
33x+5+4x−5=9
3
+
4
3
=
9
\frac{3x+4x}{3}=9
33x+4x=9
7
Combine like terms
3
+
4
3
=
9
\frac{{\color{#c92786}{3x}}+{\color{#c92786}{4x}}}{3}=9
33x+4x=9
7
3
=
97
3
=
9
\frac{7x}{3}=9
37x=9
3
⋅
7
3
=
3
⋅
9
3 \cdot \frac{7x}{3}=3 \cdot 9
3⋅37x=3⋅9
9
Cancel multiplied terms that are in the denominator
3
⋅
7
3
=
3
⋅
9
3 \cdot \frac{7x}{3}=3 \cdot 9
3⋅37x=3⋅9
7
=
3
⋅
9
7x=3 \cdot 9
7x=3⋅9
10
Multiply the numbers
7
=
3
⋅
9
7x={\color{#c92786}{3}} \cdot {\color{#c92786}{9}}
7x=3⋅9
7
=
2
7Divide both sides of the equation by the same term
7
=
2
7
7x=27
7x=27
7
7
=
2
7
7
\frac{7x}{{\color{#c92786}{7}}}=\frac{27}{{\color{#c92786}{7}}}
77x=727
12
Simplify
Cancel terms that are in both the numerator and denominator
=
2
7
7
x=\frac{27}{7}
x=727
Step-by-step explanation:
Eliminate redundant parentheses
(3x + 5) + (4x - 5) = 9
3x +5+4x-5=9
92%
7:25 PM
1
2
Subtract the numbers
<
3x +5+4x-5 = 9
3x + 4x = 9
<
3
Combine like terms
3x + 4x = 9
7x = 9
Divide both sides of the equation by the same term
7x = 9
Simplify
x = 9/7
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