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Step-by-step explanation:
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Answer: PLEASE BRAINLIEST MY ANSWER
Step-by-step explanation:
1) ⇒ ⇒Given, sides of an isosceles triangle are base 2cm and length of one of the equal sides is 4cm
Let ΔABC, side BC be the base and side AB, AC are equal in length
∴ BC = 2cm ; AB = 4cm ; AC = 4cm
s= (4+4+2)/2 = 10/2 = 5
Area of the triangle
Δ= √[s×(s−a)×(s−b)×(s−c) ]
= √[5×(5−4)×(5−4)×(5−2) ]
= √[5×1×1×3]
= √15 cm²
2) ⇒ We know that the formula of area of equilateral triangle-
Area (equilateral triangle) = (√3/4)×(side)²
given, side of equilateral triangle is x unit
∴ Area (equilateral triangle) = (√3/4)*x² sq. unit
3) Given, two sides of a triangle are 8cm and 11cm also perimeter of a triangle is 32cm
let third side of a triangle be c=x cm and also other sides be a=8cm and b=11cm
∵ We know that,
perimeter( triangle) = a + b + c
∴ 32 = 8 + 11 + c
∴ 32 = 19 + c
∴ c = 32-19
∴ c = 13
∴ third side is 13cm