Question

please answer this question don't copy?!! please friends be honest ​

Answer 1

$Height \: of \:the \: vertical \:wall = BC$

$Length \:of \: the \:pole (AC) = 10 \: m$

$Distance \: between \: foot \:of \:the \:pole \\to \: base \:of \:the \:wall = AB$

$In \: \triangle ABC , \angle B = 90\degree$

$Cos 60\degree = \frac{AB}{AC}$

$\implies \frac{1}{2} = \frac{AB}{10}$

$\implies \frac{10}{2} = AB$

$\implies AB = 5 \:m$

Therefore.,

$\red {Distance \: between \: foot \:of \:the}\\\red{ pole \:to \: base \:of \:the \:wall}\green { =5\:m}$

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Answer 2

Answer:

Cos 60 = p/h

1/2 = x/10

2x = 10

Therefore x = 5m

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