Question

please answer this question. don't spam​

Answer 1

tane=w^R/g.

Explanation:

Since, the boy is rotating the string with the angular speed of w. So, the string will be having a tension T in the upward direction. So, the components will be given as Tsine= mv^2/R which will be Tsine-mw^2R where 0 is the angle with the vertical.

Again, the Tcose will be equal to mg. When we divide both of the equation we will get that tane=w^R/g. Where R is the radius of the circle of rotation.

Answer 2

☘️$\Large{\blue{\bold{Solution:}}}$

A pseudo force $(\sf{ma_r})$acts on the bob due to the rotation of circular platform.

In the frame of bob is at rest.

∴$\sf{Tsin\theta = ma_r\; (a_r = rw²)}$

$☆\;\sf{Tsin\theta = mrw²}$ ➝ ①

$☆\;\sf{Tcos\theta = mg}$ ➝ ②

By Dividing ② by ①

$→\;\Large\sf{\frac{Tsin\theta}{Tcos\theta} = \frac{mrw²}{mg}}$

• $\boxed{\pink{\sf{\frac{Sin}{Cos} = Tan}}}$

$→\;\Large{\sf{Tan\theta = \frac{rw²}{g}}}$

• $\red{\bold{Option\;C}}$ is correct.

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Hope This Helps!!