Question

please answer this question don't spam otherwise I will report you​

Answer 1

Answer:

x^2+(x/4)-1

Step-by-step explanation:

(x-a)(x-b)=0

a and b are the roots

a+b=1/4

ab=-1 => a=-1/b

b-1/b = 1/4

b^2-1=b/4

b^2-b/4-1=0

b = (1/4+- sqrt(65/16))/2

plugging this into a results in

a = (1-sqrt(65))/8, b = (1+sqrt(65))/8

a = (1+sqrt(65))/8, b = (1-sqrt(65))/8

and then if you plug those into (x-a)(x-b)

you get

x^2+x*(1+sqrt(65)/8)+x*(1-sqrt(65))/8-(1+sqrt(65))/8*(1-sqrt(65))/8

which becomes

x^2+x/4-1