Question

please answer this question fast ​

Answer 1

Step-by-step explanation:

$= a {sin}^{2} \alpha + b {cos}^{2} \alpha = c \\ = a {tan}^{2} \alpha + b = c {sec}^{2} \alpha \\ = a {tan}^{2} \alpha + b = c + c {tan}^{2} \alpha \\ = (a - c) {tan}^{2} \alpha = c - b \\ = {tan}^{2} \alpha = \frac{c - b}{a - c} \\ \\ \\ hope \: it \: helps \: you...$