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In a Trepizium AB || CD
so ABD = ABC
IN the traingle ABD and ABC a traingle AOB is a common trainglein both traingle.
so ABD = ABC
AC = BD ( Proved)
so now the traingle AOD = BOC
because in both above we prove that ABD = ABC
So if we subtract ABD - AOB = AOD
ABC - AOB = BOC
so , OA = OB, OD = OC
SO
OA/ OC = OB/ OD
HENCE PROVED
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