Math, asked by krishnandecorator59, 9 months ago

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Answered by Anugodara
2

Answer:

In a Trepizium AB || CD

so ABD = ABC

IN the traingle ABD and ABC a traingle AOB is a common trainglein both traingle.

so ABD = ABC

AC = BD ( Proved)

so now the traingle AOD = BOC

because in both above we prove that ABD = ABC

So if we subtract ABD - AOB = AOD

ABC - AOB = BOC

so , OA = OB, OD = OC

SO

OA/ OC = OB/ OD

HENCE PROVED

Answered by Anonymous
1

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