please answer this question fast
Attachments:
Answers
Answered by
1
AB=AC SO 1/2AB=1/2AC
In triangle BFC &BEC
FB=EC(s)
Angle FBC=AngleECB(a)
BC IS COMMON
BY SAS CONGRUENCY THOSE TWO TRIANGLES ARE CONGRUENT
In triangle BFC &BEC
FB=EC(s)
Angle FBC=AngleECB(a)
BC IS COMMON
BY SAS CONGRUENCY THOSE TWO TRIANGLES ARE CONGRUENT
Similar questions