Math, asked by jatinverma3, 1 year ago

please answer this question fast

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Answered by Audi01
1
AB=AC SO 1/2AB=1/2AC
In triangle BFC &BEC
FB=EC(s)
Angle FBC=AngleECB(a)
BC IS COMMON
BY SAS CONGRUENCY THOSE TWO TRIANGLES ARE CONGRUENT
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