Question

please answer this question fast

Answer 1

It can be observed that 1 round of wire will cover 3 mm height of cylinder.

number of rounds=
$\frac{height \: o \: cylinder}{diameter \: o \: wire \: } = \frac{12}{0.3} = 40 \: rounds$


Length of wire required in 1 round = Circumference of base of cylinder

= 2πr = 2π × 5 = 10π

Length of wire in 40 rounds = 40 × 10π

$\frac{400 \times 22}{7} = \frac{8800}{7}$


= 1257.14 cm = 12.57 m

 

Radius of wire= .0.3/2 = 0.15 

Volume of wire = Area of cross-section of wire × Length of wire

= π(0.15)2 × 1257.14

= 88.898 cm3

Mass = Volume × Density

= 88.898 × 8.88

= 789.41 gm