Question

please answer this question fast

Answer 1

LET AC AND BD INTERSECT AT A POINT O
IN TRIANGLE AOD
BY PYTHAGORAS THEOREM 
AB^2 = AO^2 + DO^2
ON MULTIPLYING BY 4 ON BOTH SIDES
4AB^2.=4AO^2 + 4DO^2
ALL SIDES OF RHOMBUS ARE EQUAL
SO---
AB^2 + BC^2 + CD^2 + DA^2 = 4AO^2 +4 DO^2

:) Hope this Helps!!!!