Math, asked by jastenpalsingh, 1 year ago

please answer this question fast

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Answered by ShuchiRecites
0
Hello Mate!

 \frac{2 +  \sqrt{3} }{2 -  \sqrt{3} }  \times  \frac{2 +  \sqrt{3} }{2 +  \sqrt{3} }  \\  =  \frac{ {(2 +  \sqrt{3}) }^{2} }{4 - 3}  \\  = 4 + 3 + 4 \sqrt{3}  \\  = 7 + 4 \sqrt{3}
 \frac{2 -  \sqrt{3} }{2 +  \sqrt{3} }  \times  \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} }  \\ 4 + 3 - 4 \sqrt{3}  \\ 7 - 4 \sqrt{3}
 \frac{ \sqrt{3}  - 1 }{ \sqrt{3} + 1 }  \times  \frac{ \sqrt{3}  - 1}{ \sqrt{3} - 1 }  \\  \frac{3 + 1 - 2 \sqrt{3} }{2}  =  \frac{4 - 2 \sqrt{3} }{2}  \\  = 2 -  \sqrt{3}
7 + 4 \sqrt{3}  + 7 - 4 \sqrt{3}  + 2 -  \sqrt{3}  \\ 16 -  \sqrt{3}

Hope it helps☺!

jastenpalsingh: no it is not helpful
jastenpalsingh: but thnxx
ShuchiRecites: Hmn
ShuchiRecites: Why was it not helpful?
DHV3: :O
Answered by chaitanyakrishn1
0
Hi there

Here is your answer

Thank you ★ ★ ★
#ckc

Plz mark brainliest if right

Hope it helps
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