Question

please answer this question fast​

Answer 1

Answer:

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Answer 2

Solution 5 :-

Given AP :- 17 , 14 , 11 , ... -40

Here, We have to find 6th term if an AP from the end, so arrange the AP

Therefore,

-40...11 , 14 , 17

Here,

First term of an AP = -40

Common Difference = 3

Now,

We have to find 6th term

Therefore,

By using formula to find number of terms of an AP

an = a + ( n - 1 )d

a6 = -40 + ( 6 - 1 )3

a6 = -40 + 5 * 3

a6 = -40 + 15

a6 = -25

Hence, The 6th term if an AP is -25 .

Solution 6 :-

Given AP :- 0.6 , 1.7 , 2.8 , 3.9 ...

[ An arithmetic progression is a list of numbers in which each term is obtained by adding a fixed number to the preceeding term except the first term ]

The first term is denoted by a

Here, a1 = 0.6

Common difference = a2 - a1 = 1.7 - 0.6 = 1.1

Solution 7 :-

4x^2 + 5x = 0

This is a quadratic equation which having highest power of degree 2 .

Therefore,

Comparing the given equation with

ax^2 + bx + c = 0

Therefore ,

4x^2 + 5x - 0 = 0

Here, a = 4 , b = 5 and c = 0

By using the quadratic formula

-b ± √b^2 - 4ac /2a

Put the required values,

x = -5 ± √5^2 - 4 * 5 * 0 / 2 * 5

x = -5 ±√25 / 10

x = -5 ± 5 / 10

Therefore,

x = 10/10 = 1 or x = 0/10 = 0

Hence, The two roots are 1 and 0 $.$