Math, asked by sarojrani0, 26 days ago

please answer this question fast​

Attachments:

Answers

Answered by Anonymous
8

Answer:

In triangle RPQ

Angle PQR + QPR + PRQ = 180° [ By Angle sum Property]

75° + QPR + 60° = 180°

135° + QPR = 180°

QPR = 180° - 135°

QPR = 45°

In triangle ABC

Angle ACB + ABC + CAB = 180° [ By Angle sum Property]

75° + 45° + CAB = 180°

120° + CAB = 180°

CAB = 180° - 160°

CAB = 60°

Solution:-

In triangle ABC and RPQ

Angle ACB = Angle PQR [ Both 75° ]

PQ = BC [ Given ]

Angle PRQ = Angle CAB [ From upper solution ]

Triangle ABC conqruent to RPQ [ By ASA ]

Step-by-step explanation:

Hope this helps you.

# By Sparkly Princess

Similar questions