please answer this question fast
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Answer:
In triangle RPQ
Angle PQR + QPR + PRQ = 180° [ By Angle sum Property]
75° + QPR + 60° = 180°
135° + QPR = 180°
QPR = 180° - 135°
QPR = 45°
In triangle ABC
Angle ACB + ABC + CAB = 180° [ By Angle sum Property]
75° + 45° + CAB = 180°
120° + CAB = 180°
CAB = 180° - 160°
CAB = 60°
Solution:-
In triangle ABC and RPQ
Angle ACB = Angle PQR [ Both 75° ]
PQ = BC [ Given ]
Angle PRQ = Angle CAB [ From upper solution ]
Triangle ABC conqruent to RPQ [ By ASA ]
Step-by-step explanation:
Hope this helps you.
# By Sparkly Princess
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