Question

please answer this question fast​

Answer 1

${x}^{2} - 2x = - 2(3 - x) \\ \\ {x}^{2} - 2x = - 6 + 2x \\ \\ {x }^{2} - 2x - 2x = - 6 \\ \\ {x}^{2} - 4x = - 6 \\ \\ {x}^{2} - 4x + 6 = 0$

thus the constant term is 6 (option d )

Answer 2

EXPLANATION.

The constant term in the quadratic equation.

x² - 2x = (-2)(3 - x). after reducing it to the form ax² + bx + c.

As we know that,

We can write equation as,

⇒ x² - 2x = (-2)(3 - x).

⇒ x² - 2x = - 6 + 2x.

⇒ x² - 2x + 6 - 2x = 0.

⇒ x² - 4x + 6 = 0.

Constant term = 6.

Option [D] is correct answer.

                                                                                                                           

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.