Question

please answer this question FAST

Answer 1

the answer is -2
for x2-x-6, x= -2,+3
for 3x2+8x+4, x=-2,-2/3
thus -2 is common for both.
hence for x=-2, both equations become zero.....

Answer 2

⭐⭐⭐⭐ SOLUTION ⭐⭐⭐⭐


==================================


x²-x-6 = 0

=> x²-(3-2)x-6 = 0

=> x(x-3)+2(x-3) = 0

=> (x-3)(x+2) = 0

So, either, x=3 or x= -2.

AGAIN, 3x²+8x+4 = 0

=> 3x²+6x+2x+4 = 0

=> 3x(x+2)+2(x+2) = 0

=> (3x+2) (x+2) = 0

So, either, x = -2/3 or x = - 2

Now, if we take the value of x "-2" for both the given polynomials, then their ultimate value is becoming zero.

So, for x = -2, both the polynomials x²-x-6 and 3x²+8x+4 become zero. [REQUIRED ANSWER]



==================================

⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐

==================================