Question

please answer this question fast​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

AVERAGE Weight of 9 student=42 kg

Average =Sum of total Terms÷Total Terms

Let Sum of Actual Weight of 9 student

$x_1+x_2+x_3+x_4.....+x_9$

AVERAGe=$x_1+x_2+x_4....+x_9\:\div9=42$

$x_1+x_2+x_4....+x_9$=42×9

$x_1+x_2+x_4....+x_9$=378 kg

Sum of Weight of 9 Student=378 kg

If 1 Student Join

Total Student=10

AVERAGe=42.5 kg

Let weight Of 10th Student=x10

Sum of weight of 10 Student.

$x_1+x_2+x_4....+x_9+x_{10}$

AVERAGe=$x_1+x_2+x_4....+x_9+x_{10}\:\div10$

Sum of First 9 Student weight=378

$378+x_{10}\div\:10=42.5$

$378+x_{10}$=42.5×10

$378+x_{10}$=425

$x_{10}$=425-378

$x_{10}$=47

X10 is weight of 10th Student=47 kg

$\boxed{\mathbf{Weight \:of \:10th \:Student=47\:kg}}$