Please answer this question fast I will mark as brainiest please
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In △BAD, P and S are mid-points of AB and BD
⇒ PS∥AD and PS= 21 AD --- ( 1 ) [ By BPT ]
Similarly in △CAD,
⇒ OR∥AD and QR= 1/2 AD --- ( 2 )
From ( 1 ) and ( 2 ), we get
⇒ PS∥QR and PS=QR= 1/2 AD ------ ( 3 )
In △BDC, we get
⇒ SR∥BC and SR= 1/2BC ----- ( 4)
And in △ABC
PQ∥BC and PQ= 1/2 BC ------ ( 5 )
⇒ PQ∥SR, PQ=SR= 1/2 BC ---- ( 6 )
[ From ( 4 ) and ( 5 ) ]
∴ □PQRS is a parallelogram.
Now, AD=BC
∴
1/2 AD= 1/2 BC
∴ PS=QR=PQ=SR [ From ( 3 ) and ( 6 ) ]
∴ □PQRS is a rhombus.
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