Math, asked by pinakimandal53, 1 year ago

Please answer this question fast. It's urgent !!!!!!!!!!!!!!!!!
Construct two equations having these solutions:
i) $x = -2$
ii) $y = \frac{1}{3}$
Also, please explain me the technique that how did you construct the equations. The answer should have four equations in total.

Answers

Answered by Jainsahab05

x+2=0
1/2x=_1
3y-1=0
9y=3
bro .it is so simple
we know that if x=-2 then (x+2) is a factor of this eqation and in second one y=1/3 then(y-1/3) is a factor of this eqation

pinakimandal53: I am in class 7 and we have not done square roots in equations.

Jainsahab05: oh then you can write 3x-1=0 .

pinakimandal53: And I told you in the question that there should be four equations in total, i.e., two equations for x=-2 and two equations for y=1/3. Please don't mind for these words.

pinakimandal53: What do you mean by "factor of the equation"?

Jainsahab05: if (x+a)is a factor of p(x) then we put x=-a and remainder become zero

pinakimandal53: Please don't mind. Actually, we have STARTED Algebra and solving small equations in class 6. Now, we are being taught that how to solve linear equations.

pinakimandal53: So, I can't understand that what is p(x). But I have heard the word "function" in algebra.

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Please answer this question fast. It's urgent !!!!!!!!!!!!!!!!!Construct two equations having these solutions: i) ii) Also, please explain me the technique that how did you construct the equations. The answer should have four equations in total.

Answers

Please answer this question fast. It's urgent !!!!!!!!!!!!!!!!!
Construct two equations having these solutions:
i) $x = -2$
ii) $y = \frac{1}{3}$
Also, please explain me the technique that how did you construct the equations. The answer should have four equations in total.