Question

please answer this question fast... its urgent... and if you don't know the answer then don't give useless answer s..... Please ​

Answer 1

Explanation:

above is the explaination

Answer 2

GIVEN :

• Two bodies of mass m1 and m2 kg.
• Two bodies are attached at the free points of free ends of a spring.
• Acceleration of first body = ‘a’ m/s².

TO FIND :

• The acceleration of the second body.

SOLUTION :

$\implies \sf a \: = \: \dfrac {(m_1 \: - \: m_2)g}{(m_1 \: + \: m_2)}$

$\implies \sf a_cm \: = \: \sum mi$

$\implies \sf a_cm \: = \: a \: (m_1 \: - \: m_2)$

$\implies \sf a_cm \: \dfrac {(m_1 \: - \: m_2)}{m_1 \: + \: m_2} \: g$

$\implies \sf m_1 g \: - \: T \: = \: m_2 a$ ---------- (i)

$\implies \sf T \: - \: m_2 g \: = \: m_2 a$ ---------- (ii)

From the both above equations,

We get,

$\boxed {\red {\sf a \: = \: \dfrac {(m_1 \: - \: m_2) \: g}{m_1 \: + \: m_2}}}$