Please answer this question fast.My board exams are approaching soon
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Answer:
Correct answer is c) i and iv
Step-by-step explanation:
In beaker A:
NaOH+H2O→Na++OH−+H2O+heat
In beaker B:
CuSO4(s)+5H2O(l)→CuSO4.5H2O(s)+heat
Therfore in both A and B exothermic reactions are taking place resulting in rise in temperature.
On the other hand in beaker C, an endothermic reaction is taking place as heat is being absorbed, resulting in a decrease in temperature.
NaCl+H2O+heat→Na++Cl−+H2O
Concept: When heat is released (Exothermic process) surrounding gets warm means temperature rises.
When heat is absorbed (Endothermic process) surrounding gets cold means temperature falls.
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