Physics, asked by 9cpurvajawaykole, 3 months ago

PLEASE ANSWER THIS QUESTION FAST!! Question - What is the work to be done to increase the velocity of a car from 20km/h to 40km/h if the mass of the car is 2000 kg?

Answers

Answered by BrainlyIAS
76

Mass of the car (m) = 2000 kg

Initial velocity of the car (u) = 20 km/h

➠ u = 20 × ⁵/₁₈ m/s

u = 5.56 m/s

Final velocity of the car (v) = 40 km/h

➠ v = 40 × ⁵/₁₈ m/s

v = 11.12 m/s

Work - Energy theorem :

                  It states that , work done on a body is equals to the change in kinetic energy .

:\implies \sf W=\Delta K

:\implies \sf W=K_f -K_i

: \implies \sf W=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

: \implies \sf W=\dfrac{1}{2}m(v^2-u^2)

:\implies \sf W=\dfrac{1}{2}(2000) \big[(11.12)^2-(5.56)^2 \big]

:\implies \sf \pink{W=92740.8\ J}\ \; \bigstar

Work to be done is 92,740.8 J .


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Answered by BrainlyHero420
76

Answer:

Given :-

  • A velocity of car from 20 km/h to 40 km/h if the mass of the car is 2000 kg.

To Find :-

  • What is the work done.

Formula Used :-

\boxed{\bold{\large{Work\: done\: =\: \dfrac{1}{2}m({v}^{2} - {u}^{2})}}}

where,

  • m = Mass
  • v = Final velocity
  • u = Initial velocity

Solution :-

Given :

● Mass (m) = 2000 kg

● Initial velocity (u) = \sf 20\: km/h =\: 20 \times \dfrac{5}{18} = 5.56 m/s

● Final velocity (v) = \sf 40\: km/h =\: 40 \times \dfrac{5}{18} = 11.12 m/s

According to the question by using the formula we get,

\sf Work\: done\: =\: \dfrac{1}{\cancel{2}} \times {\cancel{2000}} \times \bigg[{(11.12)}^{2} - {(5.56)}^{2}\bigg]

\sf Work\: done\: =\: 1000 \times 92.7408

\sf\bold{\red{Work\: done\: =\: 92740.8\: J}}

\therefore The work to be done is 92740.8 J .


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