Question

Please answer this question fast (with explaination)it is urgent​

Answer 1

GiVeN :-

✒ Speed of a cyclist is constant, which is = 5 m/s

✒ Diameter of the circular track = 70 m

To DeTeRmInE :-

The distance and displacement when the time is (a) 44 s (b) 66 s

SoLuTiOn :-

Perimeter of the track = length of the track

⇒Length = 2πr

⇒Length = 2 × 22/7 × 35     (Radius = 70/2 = 35)

⇒Length = 220 m

(a) Time(t) = 44 s,

Speed(v) = 5 m/s

Distance(s) = Speed × Time

⇒s = 44 × 5

⇒s = 220 m

Hence, in 44 s, the cyclist completes 1 round.

☛ As the cyclist completes 1 round in 44 s, then the displacement = 0

(Displacement is the shortest length of the path between the starting point and the final position.) As the starting point and the final point are the same,  so

⇒Displacement = 0 m

$\rule{150}2$

(b) t = 66 s,

v = 5 m/s

s = v × t

⇒s = 5 × 66

⇒s = 330 m

☛ Therefore, in more 22 s, the cyclist covers 110 m more. That is, the cyclist covered a half round (full round = 200 m, half round = 110 m). Now, for a half round, displacement = Diameter of the circle.

⇒Displacement = 70 m