please answer this question fastly
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sec (π/2+©) = - cosec ©
You can understand this by,
cos (π/2+©) = -sin ©
So,
LHS = (1+cot©+cosec©)(1+cot © - cosec©)
= [(1+cot©)^2 - cosec^2 ©]
= 1+cot^2© - cosec^2© + 2cot ©
= cosec^2 © - cosec^2 © + 2cot © = 2 cot ©
= RHS
Therefore, LHS = RHS
If you have any doubts, kindly ask in the comments section.
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