Question

Please answer this question fastly....
If it is correct, I will mark you as brainliest.
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Answer 1

Answer:

"refer the attachment above"

Answer 2

Answer:

so let's start by rationalising all denominators one by one-:

2. × √5-√3

√5+√3. √5-√3

2√5-2√3 => 2√5-2√3

5-3. 2

_________________

1. × √3-√2

√3+√2. √3-√2

√3-√2 => √3-√2

3-2

__________________

3. × √5-√2

√5+√2. √5-√2

3√5-3√2. =>3√5-3√2

5-2. 3

___________________

now do the equation-:

step 1- make same denominators-:

2√5-2√3.×3 +. √3-√2.×6 -. 3√5-3√2×2

2. ×3 1. ×6 3×2

6√5-6√3+6√3-6√2-6√5-6√2

6

-6√2-6√2

6

=0