Question

please answer this question fat​

Answer 1

Answer:

let the root of the given equation be a & b

a+ b= - (-7)/6 = 7/6 ......1

ab= 2/6 =1/3 ......2

now the required equation has roots = 1/a & 1/ b

sum of the roots , s = (1/a)+(1/b

(a+b)/ ab

7/6/1/3

( from 1& 2)

s= 7/2 ......3

products of roots , p = (1/a)×(1/b)

1/(ab)

1÷(1/3)

p= 1/3 ( from3&4)

the required equation will be the form

y2- sy+ p =y2- (7/2)y+3=0

2y2-7y+6=0

( from 3&4)

hence the required equation us 2y2- 7y+ 6= 0