please answer this question fat and fast tomorrow is my maths final paper
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in triangle a b d
A D + AB > BD _eq1
because in a triangle sum of two side is always greater than the third side
similarly in triangle b c d
BC+CD>BD _eq2
on adding equation 1 and 2
we get
AB+BC+CD+DA>AC+BD
A D + AB > BD _eq1
because in a triangle sum of two side is always greater than the third side
similarly in triangle b c d
BC+CD>BD _eq2
on adding equation 1 and 2
we get
AB+BC+CD+DA>AC+BD
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