Question

Please answer this question fat tomorrow is my exam the 3rd one

Answer 1

Let the digit at ones place be x
Let digit at tens place be (8-x)

original no. = 10(8-x)+x
= 80-9x

ON INTERCHANGING THE DIGITS
new no = 10x+8-x
=9x+8

according to question
New no. - original no = 18

so 9x+8-(80 -9x) =18
9x +8-80+9x=18
18x-72=18
18x=90
x=90/18
x=5

so digit at ones place is 5
digit at tens place = 8-5= 3

therefore
Original no = 35
New no. = 53

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