Math, asked by amishafilomeena1003, 1 month ago

please answer this question

Find some ordered (x ,y) such that x +2y = 5 and plot them . What do you get when you join these points? How many such ordered pairs can be found and plotted?​

Answers

Answered by mathdude500
5

\large\underline{\sf{Solution-}}

The given equation is

\rm :\longmapsto\:x + 2y = 5

Substituting 'x = 0' in the given equation, we get

\rm :\longmapsto\:0 + 2y = 5

\rm :\longmapsto\:2y = 5

\rm :\longmapsto\:y = 2.5

Substituting 'y = 0' in the given equation, we get

\rm :\longmapsto\:x + 2(0) = 5

\rm :\longmapsto\:x + 0 = 5

\rm :\longmapsto\:x = 5

Substituting 'y = 1' in the given equation, we get

\rm :\longmapsto\:x + 2(1) = 5

\rm :\longmapsto\:x + 2= 5

\rm :\longmapsto\:x = 5 - 2

\rm :\longmapsto\:x = 3

Substituting 'y = 2' in the given equation, we get

\rm :\longmapsto\:x + 2(2) = 5

\rm :\longmapsto\:x + 4 = 5

\rm :\longmapsto\:x  = 5 - 4

\rm :\longmapsto\:x  = 1

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 2.5 \\ \\ \sf 5 & \sf 0 \\ \\ \sf 3 & \sf 1\\ \\ \sf 1 & \sf 2 \end{array}} \\ \end{gathered}

➢ Now draw a graph using the points.

➢ See the attachment graph.

From graph, we conclude that

1. When we join these points, we get a line

2. Infinitely many ordered pair exist.

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