Math, asked by priyansh65, 1 year ago

please answer this question for me ,I want it now. it's urgent​

Attachments:

sivaprasath: x == 3
sivaprasath: x = 3 **
sivaprasath: 5^{2x - 1} = 5^{2(3) - 1} = 5^5 = 3125, 25^{x - 1} = 25 ^{3 - 1} = 25^2 = 625 &
5^5 - 25^2 = 3125 - 625 = 2500,.
sitara14satish: one doubt........... x=3 is correct
sitara14satish: but how did u equate the bases
sivaprasath: what ?
sitara14satish: how did u simplify 2500
priyansh65: I got it
sivaprasath: ok, Solution is updated below ↓
sitara14satish: thank you..

Answers

Answered by sivaprasath
4

Answer:

x = 3

Step-by-step explanation:

Given :

To solve for x, if 5^{2x - 1} - 25^{x - 1} = 2500

Solution :

We know that,

5² = 25

Hence,

we can rewrite the equality as,

5^{2x - 1} - 25^{x - 1} = 2500

5^{2x - 1} - 5^{2(x - 1)} = 2500

5^{2x - 1} - 5^{2x - 2} = 2500

5^{2x - 2} \times 5 - 5^{2x - 2} \times 1 = 2500

5^{2x - 2} \times (5 - 1) = 2500

5^{2x - 2} \times 4 = 2500

5^{2(x - 1)}  = \frac{2500}{4}

25^{(x - 1)}  = 625

25^{(x - 1)}  = 25^2

(x - 1) = 2

x = 3

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