Question

please answer this question from logarithms, fast!!!​

Answer 1

Answer:

this is your answer

please mark on brainliest

Answer 2

Step-by-step explanation:

${x}^{log_{a}(y) } = {y}^{ log_{a}(x) }$

=> take log both side

=> log( {x}^{log_{a}(y) } ) = log( {y}^{ log_{a}(x) } )

=> logay * logx = logax*logy

=> (logy/loga)*logx = (logx/loga)*logy

=> logy*logx = logx*logy

by equation we can write that when x=1 (log1=0),value of y could be anything.

OR

when y=1 value of x can be anything.

=> x=1. => y = any positive number.

OR

=> y =1 => x = any +ve number.